2 kg ice at – 20 ºC is mixed with 5 kg water at 20 ºC. Then final amount of water in the mixture would be: Given: specific heat of ice = 0.5 cal/g ºC, specific heat of water = 1 cal/g ºC, latent heat of fusion of ice = 80 cal/gm]
Text Solution
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We have, the heat lost by water 
, heat gained by ice 
.
From the principle of calorimetry, we have, the heat lost by water=heat gained by ice.
Hence, 
.
1 kg of ice melts to form water.
Hence, final amount of water 
. Here, 
and 
are the mass, specific heat and temperature difference for water respectively. Similarly, 
and 
are the corresponding quantities for ice. Here, L is the latent heat of fusion.
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